php.js

Thanks for share, this is very useful ;)

Thanks for the input, but we'd really want it to work like in PHP.

It gave me [object Object] as an output, i dont understand whats happening here.

Hi, This is a comment to correct the function posted below. That function has an error, it returns the last key, eaven the value not match. Sorry, here's the corrected version: function array_search(val, array) { if(typeof(array) === 'array' || ... [More] typeof(array) === 'object') { var rekey; for(var indice in array) { if(array[indice] == val) { rekey = indice; break; } } return rekey; } } [Less]

Hi, For a simple array_search function, without the third parameter, i use made this variant (works with array and objects: function array_search(val, array) { if(typeof(array) === 'array' || typeof(array) === 'object') { for(var indice in array) { if(array[indice] == val) break; } if(indice) return indice; } }

Hi, For is_float i use this version: function is_float(n) { return n===+n && n!==(n|0); } - is_float() doesn't always work if you are validating form input. This is because form inputs are strings, even if the user typed a number.

Hi, For is_int i use this version: function is_int(n) { return typeof(n)==="number" && Math.round(n) == n; }

Hi, To get and also check the type of a variable, I use this: function gettype(obj, type) { // www.coursesweb.net/javascript/ // if type not specified (null), returns a string with the object (obj) type if(type == null) return ... [More] obj.constructor.toString().split(' ')[1].replace(/\(\)/g,'').toLowerCase(); else { //returns true if is it is type, else, false if (obj.constructor.toString().match(new RegExp(type, 'i', 'g'))) return true; else return false; } } - If the type of "obj" is the name specified in the "type" parameter, the function returns True, otherwise, returns False. - If no argument specified for "type", the function returns a string with the type of "obj" [Less]

Hi, For is_bool, i use: function is_bool(obj) { return (obj === true || obj === false); }