php.js

The given host 'research.nihonsoft.org' returns a 'Server not found'. Thats not your fault, but the Google results for "SSJS SendMail" aren't that informative and people should know what's going on here.

This is very help for me, thanks for your sharing informations Thanks <a href="htttp://www.pluskb.com">web development india bangalore</a>

Hello, When testing a Date-Object, it always returns true: it's an object but has no keys. No idea if this is the best solution. It works for me. I check if getMonth is available. Maybe there is a better way? if (typeof mixed_var == 'object') { ... [More] for (key in mixed_var) { return false; } if (mixed_var.getMonth) { return false; } return true; } [Less]

Correction/improvement: function long2ip(ip) { return [ip >>> 24, ip >>> 16 & 0xFF, ip >>> 8 & 0xFF, ip & 0xFF].join('.'); }

Hi, I fix this code with a typeof control in the for cicle for (key in array) { if ( parseFloat(array[key]).toString() == 'NaN' ) continue; sum += parseFloat(array[key]); } In this mode any other type of content of the array ... [More] are skipped. Example: array_sums([4, 1, 'abc', '12.3', 3, 2]); return 22.3 = 4+1+12.3+3+2; // abc is skipped and 12.3 converted to float Bye! [Less]

God bless you all. God bless php. Thank you so very much ;)

I always suggest this website as one of the best javascript vendor. Beside of that this function is much important in php so as in js now. Thanks for the developers who have created it. Best regards to them and also this site owner. Tremendous job guys. keep on.

We are using this code to format our URL and it is superb. Thanks phpJS :)

If you like short scripts, use this modified function working same as one in PHP: function str_replace (f, r, s) {f=[].concat(f), r=[].concat(r); for(var i in f){s=s.split(f[i]).join(r[r[i]!=undefined?i:0]);} return s;} Note: it is evident f is search, r is replace and s is subject. Enjoy!